-16t^2+240t+4000=1536

Solution for -16t^2+240t+4000=1536 equation:

-16t^2+240t+4000=1536

We move all terms to the left:

-16t^2+240t+4000-(1536)=0

We add all the numbers together, and all the variables

-16t^2+240t+2464=0

a = -16; b = 240; c = +2464;
Δ = b2-4ac
Δ = 2402-4·(-16)·2464
Δ = 215296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{215296}=464$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-464}{2*-16}=\frac{-704}{-32}
=+22
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+464}{2*-16}=\frac{224}{-32}
=-7
$